Skip to main content

AWS Certified Welding Inspector Exam

Welding Metallurgy Practice Questions

40 practice questions with detailed explanations — aligned to the AWS Certified Welding Inspector Exam.

  1. Q1.In the Iron-Carbon phase diagram, the temperature at which liquid steel begins to solidify upon cooling is called the:

    A.Solidus line
    B.Liquidus line
    C.Eutectoid point
    D.Transformation line
    BLiquidus line

    Explanation: The Liquidus line represents the temperature above which the alloy is completely liquid. Below this line, solidification begins.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  2. Q2.The region of the base metal that has not been melted but whose mechanical properties or microstructure have been altered by the heat of welding is called the:

    A.Fusion Zone
    B.Weld Interface
    C.Heat Affected Zone (HAZ)
    D.Unaffected Base Metal
    CHeat Affected Zone (HAZ)

    Explanation: The Heat Affected Zone (HAZ) is the area of base metal adjacent to the weld that was not melted but was heated high enough to cause microstructural changes.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  3. Q3.Hydrogen-induced cracking (cold cracking) in carbon steels is most likely to occur in the:

    A.Weld metal centerline
    B.Heat Affected Zone (HAZ)
    C.Unaffected base metal
    D.Fusion boundary
    BHeat Affected Zone (HAZ)

    Explanation: Hydrogen cracking typically occurs in the coarse-grained region of the HAZ where the microstructure is hardest and most brittle (martensite).

    Join 1,000+ users passing the AWS Certified Welding Inspector

  4. Q4.Which of the following elements is the primary hardening agent in steel?

    A.Manganese
    B.Silicon
    C.Carbon
    D.Sulfur
    CCarbon

    Explanation: Carbon is the most significant alloying element controlling the hardness and strength of steel. Higher carbon content increases hardness but decreases weldability.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  5. Q5.Preheating is primarily used to:

    A.Increase the cooling rate
    B.Decrease the cooling rate
    C.Increase the hardness of the HAZ
    D.Burn off impurities
    BDecrease the cooling rate

    Explanation: Preheating slows down the cooling rate of the weld and HAZ, allowing hydrogen to diffuse out and preventing the formation of brittle martensite.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  6. Q6.A steel with a Carbon Equivalent (CE) greater than ___ is generally considered difficult to weld without special precautions.

    A.0.20
    B.0.30
    C.0.40
    D.0.15
    C0.40

    Explanation: A CE of 0.40 or higher generally indicates a higher risk of cracking and requires preheat and low-hydrogen practices.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  7. Q7.The crystalline structure of austenite is:

    A.Body Centered Cubic (BCC)
    B.Face Centered Cubic (FCC)
    C.Body Centered Tetragonal (BCT)
    D.Hexagonal Close Packed (HCP)
    BFace Centered Cubic (FCC)

    Explanation: Austenite (Gamma iron) has a Face Centered Cubic (FCC) crystal structure, which can hold more carbon in solution than Ferrite.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  8. Q8.Which type of stainless steel is non-magnetic and cannot be hardened by heat treatment?

    A.Ferritic
    B.Martensitic
    C.Austenitic
    D.Precipitation Hardening
    CAustenitic

    Explanation: Austenitic stainless steels (e.g., 300 series) are non-magnetic and hardenable only by cold working, not by heat treatment.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  9. Q9.The rapid cooling of austenite in carbon steel results in the formation of:

    A.Pearlite
    B.Ferrite
    C.Martensite
    D.Cementite
    CMartensite

    Explanation: Rapid quenching prevents the diffusion of carbon needed to form pearlite, instead shearing the lattice into a hard, brittle structure called Martensite.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  10. Q10.Sensitization in austenitic stainless steels (carbide precipitation) leads to:

    A.Hydrogen cracking
    B.Intergranular corrosion
    C.Lamellar tearing
    D.Porosity
    BIntergranular corrosion

    Explanation: Heating stainless steel in the 800°F-1600°F range causes chromium carbides to form at grain boundaries, depleting chromium and reducing corrosion resistance (intergranular corrosion).

    Join 1,000+ users passing the AWS Certified Welding Inspector

  11. Q11.Low hydrogen electrodes are used to prevent:

    A.Porosity
    B.Underbead cracking (Hydrogen cracking)
    C.Lack of fusion
    D.Slag inclusions
    BUnderbead cracking (Hydrogen cracking)

    Explanation: The primary purpose of low hydrogen electrodes is to minimize hydrogen introduction, reducing the risk of underbead or cold cracking.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  12. Q12.Lamellar tearing typically occurs in:

    A.The weld metal
    B.The base metal, parallel to the rolling direction
    C.The HAZ
    D.Cast iron
    BThe base metal, parallel to the rolling direction

    Explanation: Lamellar tearing is a separation in the base metal caused by through-thickness strains (shrinkage) pulling apart non-metallic inclusions flattened by rolling.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  13. Q13.Which element is considered an impurity in steel that can cause 'hot cracking' or shortness?

    A.Manganese
    B.Sulfur
    C.Chromium
    D.Nickel
    BSulfur

    Explanation: Sulfur forms iron sulfide films at grain boundaries which have a low melting point, causing cracking during solidification (hot cracking). Manganese is added to combine with sulfur (MnS) to prevent this.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  14. Q14.Stress relief heat treatment is performed:

    A.Above the upper transformation temperature
    B.Below the lower transformation temperature
    C.At the melting point
    D.At room temperature
    BBelow the lower transformation temperature

    Explanation: Stress relief is done below the transformation temperature (typically 1100-1200°F for steel) to relieve residual stresses without altering the metallurgical structure.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  15. Q15.In the designation '6061-T6' aluminum, the 'T6' indicates:

    A.The chemical composition
    B.The temper or heat treatment condition
    C.The ultimate tensile strength
    D.The filler metal to use
    BThe temper or heat treatment condition

    Explanation: T6 indicates the aluminum has been solution heat treated and artificially aged to achieve specific mechanical properties.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  16. Q16.What effect does a high heat input have on the grain size of the HAZ in carbon steel?

    A.Refines the grain size
    B.Promotes grain growth (coarse grains)
    C.Has no effect
    D.Causes graphitization
    BPromotes grain growth (coarse grains)

    Explanation: High heat input keeps the metal at high temperature longer, promoting grain growth. Coarse grains generally result in lower toughness.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  17. Q17.The term 'pass' in welding refers to:

    A.A single progression of welding along a joint
    B.The layer of weld metal
    C.The complete weld
    D.The welding speed
    AA single progression of welding along a joint

    Explanation: A pass is a single progression of the welding operation along a joint. A layer may consist of one or more passes.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  18. Q18.Which test is used to determine the notch toughness of a material?

    A.Tensile test
    B.Charpy V-Notch test
    C.Guided bend test
    D.Brinell hardness test
    BCharpy V-Notch test

    Explanation: The Charpy V-Notch test measures the energy absorbed by a specimen during fracture, indicating its toughness and transition temperature.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  19. Q19.Which of the following is NOT a form of heat treatment?

    A.Annealing
    B.Normalizing
    C.Quenching
    D.Peening
    DPeening

    Explanation: Peening is a mechanical working process used to induce compressive stresses, not a thermal heat treatment process.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  20. Q20.When welding Quenched and Tempered (Q&T) steels (e.g., A514), heat input must be:

    A.Maximized to prevent cracking
    B.Controlled/Limited to prevent softening of the HAZ
    C.Ignored
    D.Kept extremely low to prevent hardening
    BControlled/Limited to prevent softening of the HAZ

    Explanation: Q&T steels derive strength from heat treatment. Excessive heat input acts like an over-tempering or annealing cycle, reducing the strength (softening) of the HAZ.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  21. Q21.The property of a metal that allows it to deform plastically without breaking is:

    A.Hardness
    B.Ductility
    C.Strength
    D.Stiffness
    BDuctility

    Explanation: Ductility is the ability of a material to deform plastically (stretch/elongate) under tensile stress before rupture.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  22. Q22.What is the primary alloying element in '300 Series' stainless steel?

    A.Carbon
    B.Chromium and Nickel
    C.Molybdenum
    D.Titanium
    BChromium and Nickel

    Explanation: 300 series stainless (Austenitic) contains Iron, Chromium (typically 18%), and Nickel (typically 8%).

    Join 1,000+ users passing the AWS Certified Welding Inspector

  23. Q23.Calculate the Carbon Equivalent (CE) for a steel with: C=0.18%, Mn=0.60%, Cr=0.10%, Mo=0.15%, V=0.05%, Ni=0.15%, Cu=0.15%. Using IIW Formula.

    A.0.30
    B.0.36
    C.0.42
    D.0.25
    B0.36

    Explanation: Formula: CE = C + Mn/6 + (Cr+Mo+V)/5 + (Ni+Cu)/15. CE = 0.18 + (0.60/6) + (0.10+0.15+0.05)/5 + (0.15+0.15)/15. CE = 0.18 + 0.10 + 0.06 + 0.02 = 0.36.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  24. Q24.During the solidification of a weld, impurities tend to collect:

    A.At the grain boundaries and centerline
    B.At the surface
    C.In the HAZ
    D.Evenly throughout the grain
    AAt the grain boundaries and centerline

    Explanation: Impurities with lower melting points are pushed ahead of the solidifying front and concentrate at the center of the weld or grain boundaries, causing centerline cracking.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  25. Q25.The lowest temperature at which a steel exhibits ductile fracture behavior is the:

    A.Melting point
    B.Upper transformation temperature
    C.Ductile-to-Brittle Transition Temperature (DBTT)
    D.Curie point
    CDuctile-to-Brittle Transition Temperature (DBTT)

    Explanation: DBTT is the temperature below which the material fracture mode changes from ductile to brittle. Operating below this temp increases risk of catastrophic failure.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  26. Q26.When welding gray cast iron, the primary difficulty is:

    A.Excessive ductility
    B.Formation of brittle white cast iron and martensite in the HAZ
    C.Low melting point
    D.Excessive porosity
    BFormation of brittle white cast iron and martensite in the HAZ

    Explanation: Gray cast iron has high carbon. Rapid cooling during welding forms hard, brittle white iron (cementite) and martensite, leading to cracking.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  27. Q27.A 'Schaeffler Diagram' is used to predict:

    A.Preheat temperatures
    B.Microstructure of stainless steel welds
    C.Tensile strength of carbon steel
    D.Cooling rates
    BMicrostructure of stainless steel welds

    Explanation: The Schaeffler diagram uses Nickel and Chromium equivalents to predict the phases (Austenite, Ferrite, Martensite) present in stainless steel welds.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  28. Q28.Which of the following reduces the cooling rate of a weld?

    A.Decreasing heat input
    B.Increasing plate thickness
    C.Increasing preheat temperature
    D.Decreasing interpass temperature
    CIncreasing preheat temperature

    Explanation: Increasing preheat reduces the temperature gradient between the weld and the base metal, thereby slowing down the cooling rate.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  29. Q29.Sigma phase embrittlement can occur in stainless steels when held for long periods at:

    A.Room temperature
    B.1000°F - 1700°F
    C.Cryogenic temperatures
    D.Near melting point
    B1000°F - 1700°F

    Explanation: Sigma phase is a hard, brittle intermetallic phase that forms in high-chromium steels exposed to temperatures between 1000°F and 1700°F.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  30. Q30.The 'Yield Strength' of a material is defined as:

    A.The point at which the material breaks
    B.The stress at which plastic deformation begins
    C.The maximum stress the material can endure
    D.The hardness of the material
    BThe stress at which plastic deformation begins

    Explanation: Yield strength is the stress level where the material transitions from elastic (recoverable) deformation to plastic (permanent) deformation.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  31. Q31.Which gas is soluble in molten aluminum but precipitates upon freezing to cause porosity?

    A.Nitrogen
    B.Oxygen
    C.Hydrogen
    D.Argon
    CHydrogen

    Explanation: Hydrogen has high solubility in molten aluminum but very low solubility in solid aluminum. Upon freezing, trapped hydrogen forms gas pores.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  32. Q32.Ferrite number (FN) is a measurement used to quantify:

    A.Carbon content in steel
    B.Delta ferrite content in austenitic stainless steel welds
    C.Hardness of cast iron
    D.Hydrogen content
    BDelta ferrite content in austenitic stainless steel welds

    Explanation: A small amount of Delta Ferrite (FN 3-10) is desired in austenitic welds to prevent hot cracking. FN is measured magnetically.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  33. Q33.Weld decay (intergranular corrosion) can be prevented by using:

    A.High carbon electrodes
    B.Stabilized grades (e.g., 321, 347) or Low Carbon (L-grade) base metals
    C.Higher heat input
    D.Slower travel speeds
    BStabilized grades (e.g., 321, 347) or Low Carbon (L-grade) base metals

    Explanation: Stabilized grades contain Titanium or Niobium to bind carbon, preventing chromium carbide formation. L-grades have <0.03% carbon.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  34. Q34.Which property is determined by the 'Percent Elongation' in a tensile test?

    A.Hardness
    B.Tensile strength
    C.Ductility
    D.Toughness
    CDuctility

    Explanation: Percent Elongation measures how much the specimen stretched before breaking, which is a direct measure of ductility.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  35. Q35.Heat input (J/in) is calculated by:

    A.(Amps x Volts x 60) / Travel Speed (in/min)
    B.Amps x Volts x Travel Speed
    C.(Amps x Travel Speed) / Volts
    D.Amps + Volts
    A(Amps x Volts x 60) / Travel Speed (in/min)

    Explanation: Heat Input formula: H = (Voltage × Amperage × 60) / Travel Speed. This formula calculates the energy per unit length of weld, measured in joules per inch (J/in).

    Join 1,000+ users passing the AWS Certified Welding Inspector

  36. Q36.The term 'Passivation' regarding stainless steel refers to:

    A.Heat treating to anneal the metal
    B.Chemical treatment to remove surface iron and restore the passive oxide layer
    C.Hardening the surface
    D.Painting the surface
    BChemical treatment to remove surface iron and restore the passive oxide layer

    Explanation: Passivation (usually with nitric or citric acid) removes free iron from the surface and enhances the formation of the chromium-oxide layer that resists corrosion.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  37. Q37.When welding titanium, shielding is required:

    A.On the face of the weld only
    B.On the face, root, and trailing HAZ until cooled below 800°F
    C.Titanium does not require shielding
    D.Only for the first pass
    BOn the face, root, and trailing HAZ until cooled below 800°F

    Explanation: Titanium is extremely reactive to atmospheric gases at high temperatures. It requires inert gas shielding on the face, root, and a trailing shield for the cooling metal.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  38. Q38.Martensite is best described as:

    A.Soft and ductile
    B.Hard and brittle
    C.Tough and elastic
    D.Liquid
    BHard and brittle

    Explanation: Martensite is a supersaturated solid solution of carbon in iron, formed by rapid quenching. It is extremely hard but very brittle.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  39. Q39.Dilution is defined as:

    A.The change in chemical composition of a welding filler metal caused by the admixture of the base metal
    B.Adding water to the flux
    C.The width of the HAZ
    D.The amount of hydrogen in the weld
    AThe change in chemical composition of a welding filler metal caused by the admixture of the base metal

    Explanation: Dilution is the percentage of base metal that melts and mixes with the filler metal to form the final weld metal composition.

    Join 1,000+ users passing the AWS Certified Welding Inspector

  40. Q40.Which factor promotes hydrogen cracking?

    A.High hydrogen level
    B.Susceptible microstructure (Martensite)
    C.Tensile stress
    D.All of the above
    DAll of the above

    Explanation: Hydrogen cracking requires three conditions: Hydrogen, susceptible microstructure, and stress (plus temperature < 400°F).

    Join 1,000+ users passing the AWS Certified Welding Inspector

Want all 463 questions?

Download VoltExam — $17.99 Lifetime

Offline access, 463+ questions, built-in calculators. One-time unlock, no subscription.

Download on the App Store

More AWS Certified Welding Inspector Exam Topics